NFA

1. $\mathcal{L}(M) = \{ abxba \mid x \in \Sigma^{*}\}$

stateDiagram-v2
    direction LR
    classDef accepting fill:#4CAF50,stroke:#333,stroke-width:2px
    classDef start fill:#FFD700,stroke:#333,stroke-width:2px

    s0: q0
    s1: q1
    s2: q2
    s3: q3
    s4: q4
    s5: q5

    [*] --> s0
    s0 --> s1: a
    s1 --> s2: b
    s2 --> s2: Σ
    s2 --> s3: b
    s3 --> s4: a
    s4 --> [*]

    class s4 accepting
    class s0 start

2. $\mathcal{L}(M) = \{ yx \mid x = 00 \lor x =11 \land y \in \Sigma^{*}\}$

stateDiagram-v2
    direction LR
    classDef accepting fill:#4CAF50,stroke:#333,stroke-width:2px
    classDef start fill:#FFD700,stroke:#333,stroke-width:2px

    s0: q0
    s1: q1
    s2: q2
    s3: q3
    s4: q4

    [*] --> s0
    s0 --> s0: 0,1
    s0 --> s1: 0
    s0 --> s3: 1
    s1 --> s2: 0
    s3 --> s4: 1
    s2 --> [*]
    s4 --> [*]

    class s2,s4 accepting
    class s0 start

stateDiagram-v2
  direction LR
  [*] --> s1
  s1 --> s2: 1
  s2 --> s3: 1
  s3 --> s4: ε
  s1 --> s4: ε
  s1 --> s1: 0
  s3 --> s3: 1

Given the following $M$

stateDiagram-v2
  direction LR
  [*] --> s1
  s1 --> s2: 1
  s2 --> s3: 1
  s3 --> s4: ε
  s1 --> s4: ε
  s1 --> s1: 0
  s3 --> s3: 1

$\mathcal{L}(M) = \{0^n1^m \mid n \geq 0, m \neq 1 \space, x \in \Sigma^{*}\}$