profile pic
⌘ '
raccourcis clavier

See also slides and Root locus

closed-loop properties of the function of K1G(s)K_1 G(s)

xKG(s)+-e(t)K/s

improving transient response

Question

How to calculate K?

  • Product of distances from open-loop pole to point in question

Second-order poles for the second-order system.

improving steady state error (SSE)

adding PID (compensator) with an integrator (1s\frac{1}{s}) in feed forward path.

ideal integral compensation

proportional-plus-integral (PI) controller causing error to go to zero.

Important

Add zero! on the pole near the origin at s=as=-a

Ks(s+a)=Kp+Kis\frac{K}{s}(s+a) = K_p + \frac{K_i}{s}

where KpK_p is the proportional gain, and KiK_i is the integral gain.

Implementation Gc(s)G_c(s)

Gc(s)=Kp+Kis=Kp(s+KiKp)sG_c(s) = K_p + \frac{K_i}{s} = \frac{K_p(s+\frac{K_i}{K_p})}{s}

lag compensation